Dear Ahmed For the question ...

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Dear Ahmed

For the question of SRT it is not a negativa value (see Table below).

For the Problem of a pick factor of three, may be this area is a tourist one. To maintain a good performance of the bilogical process it is recommanded not apply different hydraulic and organic loads and so as a hydraulic system is needed befor the process.

 

Parameter / Rate Parameter Unit Vaue
 Qavg   -  m3/d 5000
 Qmax    m3/d 14400
 F/M   Cm  kg DBO5/KG MLVSS/d 0,3
 MLVSS/MLSS    - 70%
 MLSS   X  mg MLSS/L 3000
  mg MLVSS/L 2100
 BODin   So  mg BOD5/L 240
 BODout   Se  mg BOD5/L 20
 Y   Y  1/d 0,4
 kd    kd  1/d 0,04
 DESIGN       
 V    =Qavg x (So-Se)/(Cm x X)  m3 1905
 =Qmax x (So-Se)/(Cm x X)  m3 5486
 HRT   HRT_avg = V_Qavg/Qavg  d 0,38
 HRT_max = V_Qmax/Qmax  d 0,38
 SRT   = (X x HRT_avg  x (So-Se))/(Y x (So - Se) - k x X x HRT_avg)  d 14,29
 = (X x HRT_max  x (So-Se))/(Y x (So - Se) - k x X x HRT_max)  d 14,29

1 Comment

thank u dear Driss. so you recommend to design an equalization tank. can we utilize a first sedimentation clarifiers as an equalization unit? (if we design first clarifiers hydrolically for maximom flow). i think this idea can reduce costs.

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