Published by Clayton Postma
What parameters are required to accurately calculate the cost of pumping borehole water?
Isn't everyone over complicating the answer? The cost of pumping water has nothing to do with anything except flow rate, power consumption, and electricity rate structure. The end result to answer the question is cost per unit volume or am I missing something here?
Published by Lyle Mariam
Cost Parameters to drill a bore hole include; (1) accommodation and travel of drilling crew, (2) contract rates for drilling contractor, (3) drilling method and type of equipment, (4) diameter of bore hole, depth of bore hole, (5) type and size of pump, (6) power source (electricity or diesel), (7) hours on site, (8) Materials.
Published by Kevin Linton, TopInfo - Partner
Cost should also include paid
Tax for production of Ground Water as it's also a natural source.
Basic Requirement according to your required Flow rate and depth of water water table. Soil stata . | ||||||||||||||||||||||||||||||||||||
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Published by Fayyaz Hussain
The basic items needed are flow rate, energy consumption, and cost of energy. That's all you need if you are trying to determine the cost to pump water. This will give you the cost per unit volume
1 ) Calculate the hourly flow in Gallons, Cubic Meters, etc. per hour
2 ) Divide the hourly power consumption in KWH by the total hourly flow, which gives KWH/Gal
3 ) Multiply KWH/Gal * Cost of electricity in $/KWH which gives $/Gallon (or whatever unit of volume)
This results in the wire-to-water cost including all efficiency losses.
Published by Lyle Mariam
You should know the following:
From this data you can arrive at the system total head.
Calculate HP, calculate wattage and multiply it by rate per watt-hr; or if diesel power ( generator) cost of fuel etc.
Published by Yashpal Morey, Proprietor at Eastern Star Consulting Engineers
Total efficiency=Motor efficiency X Pump efficiency
Cost/1,000 gallons = (0.189 x Cost/kWh x Head) / (Pump eff x Motor eff x 60
Published by Prem Baboo, Researcher at www.researchGate.net
1. Static Head in metres water press= Ordinance Datum Height (ODH) of the Pipe Invert at the point of discharge minus the ODH of Water level in borehole (The Height Difference)
2. System Head in metres of water = Calculate diameter of pipe to achieve a desired flow velocity from the desired flow rate (1m/s is reasonable), then From tables, calculation spreadsheet or software calculate the flow friction head loss equivalent for the distance of the pipeline.
3. Total Head in metres = 1 + 2
4. Select a borehole pump to deliver the desired flow at the Total Head, this is called The Duty Point
5. From the manufacturers pump curves look for the Duty Point on the flow / head curve and note the corresponding absorbed power (electrical kW)
6. Estimate the annual hours run for the pump (to achieve volume of water required) and multiply that by the Duty Point kW rating to find kWh.
7. Find the unit price per kWh from the energy supplier and multiply by the annual kWh calculated to arrive at the cost of electricity per year. Add any standing charge costs for the electrical supply and metering.
8. Add in some costs for pump maintenance each year to 7. to arrive at your total cost.
Published by David Harpur, Water Engineer
The cost calculation in discharging 1 Cumec water through a pump from a borehole shall require the following;
There are standard curves available for calculating the approximate cost of pumping from the borehole supplied by the manufacturer of the pump.
Published by Arvind Mishra, Managing Director
Pumping Costs
Pumping costs for water can be computed based on the following equation:
CAF = (K *L * PKwh)/E where:
CAF = cost per acre-foot ($) K = number of kilowatt hours needed to lift one acre-foot of water one foot at 100 percent pump efficiency
L = lift of water (feet) E = overall pumping efficiency
PKwh = price per kilowatt hour of electricity ($)
Published by Elvis Mwaka, specialist engineers at uwp consulting engineers
You could use an online calculator, such as from pump supplier Grundfos, or speak to them. I've included details below should you wish too determine / understand yourself.
As an example a 5Ml/d flowrate (208m3/hr), with a total lift of 100m and a typical total efficiency of 0.65, has a electrical input power of 87.2kW. Used 24/7/365 (8760 hours) at £0.1/kWh, would cost £76,370 per year.
The costs are proportional to flowrate, total lift, hours run and tariff cost. The costs will however increase ( and could double ) as efficiency reduces, which can easily happen if the pumpset is not well selected for the required flow / lift. A good engineer is required here, as a poor / simple design can also easily lead to pumpset failure.
Calculations Explained in detail:
Total Cost = Energy Cost £/kWh * Energy usage (kWh) per year.
You will need to know:
Energy usage (kWh) per year = hourly kW usage * hours of operation.
Hourly kW usage depends upon Flowrate, Pumping Lift and total efficiency...
Hourly kW usage (kW) = flowrate(m3/hr)*998.2/3600/1000*9.81*Total Lift(m)/System Efficiency(e.g. 0.65)
Total Pump Lift (m) (Pumping Water Level (measured from the discharge pressure gauge) + losses in motor cooling shroud+rising main losses + discharge pressure gauge reading (static lift to discharge point + losses in the discharge pipeline)
Total Efficiency (pump, motor, all other electrical efficiencies).
This covers most items.
Published by Darren Hewerdine
Static head, transmission pipeline diameter, pumped water, pump motor specifications.
Published by Julius Musiimenta, managing Director at hydraulic & Sanitation consult ltd