Storage tank emptying time

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how can be determine
the emptying time of Water storage tank sizing 18m x 18m x 2.4m with 
inflow rate of 4lps when inflow and outflow ends at the same time. The 
outlet is 6 inch gate valve

thank you!

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Category: Academic

6 Answers

Hi, I think the comparison ...

Hi,

I think the comparison between inflow and outflow is quite large, hence with Qout >> Qin with Qout is estimated using this formula:

Qout=mu*A*sqrt(2*g*h)

you can neglect the inflow (Qin) and use the following formula:

t=[(2*A0)/(mu*A*sqrt(2*g))] * (sqrt(h1) - sqrt(h2))

where A0 is your tank cross section (which is constant with respect to tank height I assume), mu is orifice outlet coefficient or gate valve coefficient in this case, g is gravitational acceleration, h1 and h2 is the water level before and after (in this case h2 is 0 since it will be emptied).

 

In case you want to include the Qin, you need to use another approach since it involves tank/reservoir storage equation. Also another treatment is needed if the areal cross section of the tank is not constant e.g. cone shaped.

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you might find this ...

you might find this calculation useful

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1 Comment

The tank will attain a level ...

The tank will attain a level around 5 hours of commencement of draining at which the cover over an assumed bottom 6 inch outlet will be inadequate to make the outlet run full. At this point if the inflow rate is regulated to reduce to zero, tank runs out very soon thereafter.

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See attached PDF

See attached PDF

 

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Where At is the area of the ...

Where At is the area of the tank (18 m X 18 m)

Ao is the cross area of the open valve

g is gravity and

Cd is the coefficient for the tipe and size of valve, I believe is 3076, see https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&ved=2ahUKEwjs0p2jq7DuAhUlnq0KHaK9D4cQFjAAegQIBRAC&url=https%3A%2F%2Fglobalsupplyline.com.au%2Fwp-content%2Fuploads%2F2014%2F10%2FGate-Globe-Check-Valves-Flow.pdf&usg=AOvVaw1sSUMuyRoM9SuVUF7yN93K

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t= integral from Z2 (2.4 m) ...

t= integral from Z2 (2.4 m) to Z1 (0m) of At(sqr z1 - sqr z2)  / ((CdAo sqr 2gz) - 4)

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