Thank you Mr Patel for your detailed answer, I just want to go through what you said to see what I understood: 1. "Take a five gallon bucket fill it with tank water and add half of the calculated amount of bleach mix it good": In my case the calculated amount of NaOCl is 150 ml, therefore 75 ml in 20-liter bucket (more or less 5 gallon) gives 0.45 g of NaOCl. 2. "Now repeat the process with 3/4 of the remaining NaOCl and check residual": Again, 56.2 ml of NaOCl in 20 L gives 0.34 g of NaOCl as result. 0.34+0.45=0.8 g of NaOCl in 500 L means 1.6 mg/L. Why do you say that I would be at 2-5% of my target? Thanks.
Published by Donato Patrissi
Thank you Mr Patel for your detailed answer,
I just want to go through what you said to see what I understood:
1. "Take a five gallon bucket fill it with tank water and add half of the calculated amount of bleach mix it good": In my case the calculated amount of NaOCl is 150 ml, therefore 75 ml in 20-liter bucket (more or less 5 gallon) gives 0.45 g of NaOCl.
2. "Now repeat the process with 3/4 of the remaining NaOCl and check residual": Again, 56.2 ml of NaOCl in 20 L gives 0.34 g of NaOCl as result.
0.34+0.45=0.8 g of NaOCl in 500 L means 1.6 mg/L. Why do you say that I would be at 2-5% of my target?
Thanks.