Donato, One liter of 6g/L ...
Published by Bhupen Patel
Donato,
One liter of 6g/L NaOCl into 500 liter water - will have 12 mg/L FRC, if there is no chlorine demand (RODI water). My suggestion is to find out what is the chlorine demand for 15 min, add your residual FRC target on it. Make sure to have proper PPE when handling hypochlorite. Take a five gallon bucket fill it with tank water and add half of the calculated amount of bleach mix it good. Add the mixture into the 500 liter tank. Give it 10 min to disperse. Check free residual, there should not be any. Now repeat the process with 3/4 of the remaining NaOCl and check residual. based on the FRC reading, add only the required amount to get to your FRC target. Check it after 10 min. You should be within 2-5% of your target.
1 Comment
Thank you Mr Patel for your detailed answer,
I just want to go through what you said to see what I understood:
1. "Take a five gallon bucket fill it with tank water and add half of the calculated amount of bleach mix it good": In my case the calculated amount of NaOCl is 150 ml, therefore 75 ml in 20-liter bucket (more or less 5 gallon) gives 0.45 g of NaOCl.
2. "Now repeat the process with 3/4 of the remaining NaOCl and check residual": Again, 56.2 ml of NaOCl in 20 L gives 0.34 g of NaOCl as result.
0.34+0.45=0.8 g of NaOCl in 500 L means 1.6 mg/L. Why do you say that I would be at 2-5% of my target?
Thanks.
Published by Donato Patrissi